![]() It’s easier to use and works the same everywhere. In order for Long.parseLong (str,2) To return -1, you should pass to it a String that start with '-' and ends with. Long.parseLong () expects input String s that represent negative numbers to start with '-'. Mixing NumberFormat and Long.parseLong () isn’t a good idea always. Long.parseLong () doesn't treat the first '1' character as a sign bit, so the number is parsed as 264-1, which is too large for long. This class provides several methods to convert a long to a String and a String to a long, as well as other utility methods. In this example we convert binary string to long in loop from 0 to 16 and then we print both binary and long representations of given number. If you don’t care about the format, consider using Long.toString() to convert a long value into string and Long.parseLong() to convert it back. The class wraps a value of the primitive type long in an object. Short solution: The best way to convert binary String to long in java is to use Long.parseLong() method. Now I want to pass that entire string to another query but the datatype required is long and i want to use in cl. ![]() Here in my above example, I am using Locale.US local. I have a string with comma separated value that I am getting direclty from database. However you shouldn’t depend on the default locale, try to specify one instead. There is chance that this conversion can lose information about the overall magnitude of the BigInteger value. If the value return by this function is too big to fit into long value, then it will return only the low-order 64 bits. Long.parseLong(str) parses any parsable long value from string to long value. The () converts this BigInteger to a long value. If you formatted it with NumberFormat, you should use NumberFormat.parse() to parse it back. Convert string to long using Long.parseLong(). NumberFormat can be locale-aware (in your example it uses the default locale for your computer) or you can explicitly specify format patterns, whereas the parseXXX() methods of Number subclasses only read “plain” numbers (optional minus sign+digits). Mixing NumberFormat and Long.parseLong() isn’t a good idea always. NumberFormat format = NumberFormat.getInstance(Locale.US) Long result2 = Long.valueOf(bumber2.replaceAll(",", "").toString()) remove all commas and then converting to long ![]() This class provides several methods to convert a long to a String and a String to a long, as well as other utility methods. While executing the above example do not forget to use the throws keyword in the main method otherwise compile-time error will. The class wraps a value of the primitive type long in an object. The integral part will be fine :) BigDecimal bd new BigDecimal ('30000.1') long l bd.setScale (0, BigDecimal.ROUNDHALFUP).longValue () (l) The title says converting string to long, first question is about coverting number to string, next statement about converting number to integer to string.
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